What is the nth term for this sequence 4 7 13 22 34
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Ans:49.
4+3=7
7+6=13
13+9=22
22+12=34
34+15=49.(we are adding multiples of 3 to the next consecutive terms).
(
tn = 4 + (3/2) n (n – 1)
= (3n2 – 3n + 8) ÷ 2